HackerRank Printing Pattern Using Loops Solution in C

 Print a pattern of numbers from  to  as shown below. Each of the numbers is separated by a single space.

                            4 4 4 4 4 4 4  
                            4 3 3 3 3 3 4   
                            4 3 2 2 2 3 4   
                            4 3 2 1 2 3 4   
                            4 3 2 2 2 3 4   
                            4 3 3 3 3 3 4   
                            4 4 4 4 4 4 4   

Input Format

The input will contain a single integer .

Constraints

Sample Input 0

2

Sample Output 0

2 2 2

2 1 2

2 2 2

Sample Input 1

5

Sample Output 1

5 5 5 5 5 5 5 5 5

5 4 4 4 4 4 4 4 5

5 4 3 3 3 3 3 4 5

5 4 3 2 2 2 3 4 5

5 4 3 2 1 2 3 4 5

5 4 3 2 2 2 3 4 5

5 4 3 3 3 3 3 4 5

5 4 4 4 4 4 4 4 5

5 5 5 5 5 5 5 5 5

Sample Input 2

7

Sample Output 2

7 7 7 7 7 7 7 7 7 7 7 7 7

7 6 6 6 6 6 6 6 6 6 6 6 7

7 6 5 5 5 5 5 5 5 5 5 6 7

7 6 5 4 4 4 4 4 4 4 5 6 7

7 6 5 4 3 3 3 3 3 4 5 6 7

7 6 5 4 3 2 2 2 3 4 5 6 7

7 6 5 4 3 2 1 2 3 4 5 6 7

7 6 5 4 3 2 2 2 3 4 5 6 7

7 6 5 4 3 3 3 3 3 4 5 6 7

7 6 5 4 4 4 4 4 4 4 5 6 7

7 6 5 5 5 5 5 5 5 5 5 6 7

7 6 6 6 6 6 6 6 6 6 6 6 7

7 7 7 7 7 7 7 7 7 7 7 7 7 

HackerRank Printing Pattern Using Loops Solution in C (Sample-1)

#include <stdio.h>

#include <stdlib.h>

int main() {

    int n;

    scanf("%d", &n);

    int size = 2 * n - 1;

    for (int i = 0; i < size; i++) {

        for (int j = 0; j < size; j++) {

            int min = i < j ? i : j;

            min = min < size - i ? min : size - i - 1;

            min = min < size - j - 1 ? min : size - j - 1;

            printf("%d ", n - min);

        }

        printf("\n");

    }

    return 0;

}

HackerRank Printing Pattern Using Loops Solution in C (Sample-2)

#include <stdio.h>

int main() {

    int n;

    scanf("%d", &n);

    for (int i = 1; i <= n; i++) {

        for (int j = 1; j <= i; j++) {

            printf("*");

        }

        printf("\n");

    }

    return 0;

}

HackerRank Printing Pattern Using Loops Solution in C (Sample-3)

#include <stdio.h>

int main() {

    int n;

    scanf("%d", &n);

    for (int i = n; i >= 1; i--) {

        for (int j = 1; j <= i; j++) {

            printf("*");

        }

        printf("\n");

    }

    return 0;

}