HackerRank Digit Frequency Solution in C

Given a string, , consisting of alphabets and digits, find the frequency of each digit in the given string.

Input Format

The first line contains a string,  which is the given number.

Constraints

All the elements of num are made of english alphabets and digits.

Output Format

Print ten space-separated integers in a single line denoting the frequency of each digit from  to .

Sample Input 0

a11472o5t6

Sample Output 0

0 2 1 0 1 1 1 1 0 0 

In the given string:

•  occurs two times.
•  and  occur one time each.
• The remaining digits  and  don't occur at all.

Sample Input 1

lw4n88j12n1

Sample Output 1

0 2 1 0 1 0 0 0 2 0 

Sample Input 2

1v88886l256338ar0ekk

Sample Output 2

1 1 1 2 0 1 2 0 5 0 

HackerRank Digit Frequency Solution in C (Sample-1)

#include <stdio.h>

#include <string.h>

#include <ctype.h>

int main() {

    char s[1000];

    int freq[10] = {0};  // Frequency of digits 0-9

    // Read the input string

    scanf("%s", s);

    // Iterate through each character

    for (int i = 0; s[i] != '\0'; i++) {

        if (isdigit(s[i])) {

            freq[s[i] - '0']++;

        }

    }

    // Print frequencies of digits from 0 to 9

    for (int i = 0; i < 10; i++) {

        printf("%d ", freq[i]);

    }

    return 0;

}

HackerRank Digit Frequency Solution in C (Sample-2)

#include <stdio.h>

int main() {

    char s[1000];

    int freq[10] = {0};

    scanf("%s", s);

    for (int i = 0; s[i] != '\0'; i++) {

        if (s[i] >= '0' && s[i] <= '9') {

            freq[s[i] - '0']++;

        }

    }

    for (int i = 0; i < 10; i++) {

        printf("%d ", freq[i]);

    }

    return 0;

}

HackerRank Digit Frequency Solution in C (Sample-3)

#include <stdio.h>

int main() {

    char s[1000];

    int freq[10] = {0};

    scanf("%s", s);

    for (int i = 0; s[i] != '\0'; i++) {

        int ascii = (int)s[i];

        if (ascii >= 48 && ascii <= 57) { // ASCII for '0' to '9'

            freq[ascii - 48]++;

        }

    }

    for (int i = 0; i < 10; i++) {

        printf("%d ", freq[i]);

    }

    return 0;

}