In this post, we will write a C++ program to search a number from a list by sequential search with practical program code example and compiled output.
C++ program to search a number from a list by sequential search.
#include<iostream>
#include<conio.h>
int main()
{
system("cls");
int n,i,a[10];
int ch='n';
std::cout<<"Enter any number you want to seach = ";
std::cin>>n;
for(i=0;i<=9;i++)
a[i] = rand()%100;
for(i=0;i<=9;i++)
{
if(n==a[i])
ch = 'y';
}
if(ch == 'y')
std::cout<<"The number is found"<<std::endl;
else
std::cout<<"The number is not found"<<std::endl;
for(i=0;i<=9;i++)
std::cout<<a[i]<<"\t";
getch();
return 0;
}
Output
Enter any number you want to search = 56 The number is found 46 30 82 90 56 17 95 15 48 26
0 Comments