HackerEarth Largest Balanced String problem solution

In this HackerEarth Largest Balanced String problem solution An empty sequence is balanced.

• A sequence of the form (A) or [A] or {A} is balanced if A is balanced.
• A sequence of the form AB is balanced if A and B both are balanced. 

You are given a string A, consisting of '(', ')', '[', ']', '{' and '}' only. You have to find the maximum length of the balanced string after performing some valid operation(s). Valid operations are

• Remove any character from string A
• Swap any two adjacent characters of string A

You can perform these valid operations in any order and any numbers of times.

HackerEarth Largest Balanced String problem solution.

#include <bits/stdc++.h>
using namespace std;
#define MAXN 100005

int main(int argc , char *args[]){
  freopen(args[1], "r", stdin);
  freopen(args[2], "w", stdout);
  
  int tc;
  cin >> tc;
  while(tc--){
    int cnt[200]={0};
    string str;
    cin >> str;
    for(int i =0 ; i < str.size() ; i ++){
      cnt[str[i]]++;
    }
    long long ans =0 ;
    ans += 2*min(cnt['('],cnt[')']);
    ans += 2*min(cnt['['],cnt[']']);
    ans += 2*min(cnt['{'],cnt['}']);
    
    cout <<ans <<"\n";
  }
  return 0;
}

Second solution

#include<bits/stdc++.h>
using namespace std;

int solve (string str) {
    map<char,int>mp;
    /*cout<<str<<"\n";
    cout<<mp['{'];*/
    for(int i=0;i<str.size();i++)
    {
        mp[str[i]]++;
    }
    int ans=0;
    ans+=min(mp['('],mp[')'])*2;
    ans+=min(mp['{'],mp['}'])*2;
    ans+=min(mp['['],mp[']'])*2;
    return ans;
   // Write your code here
}

int main() {

    ios::sync_with_stdio(0);
    cin.tie(0);
    int T;
    cin >> T;
    for(int t_i=0; t_i<T; t_i++)
    {
        string str;
        cin>>str;
        //getline(cin, str);

        int out_;
        out_ = solve(str);
        cout << out_;
        cout << "\n";
    }
}