In this HackerEarth Sorted Arrays problem solution, Alice has recently found an array containing N integers. As we all know Alice loves sorted arrays so, he wants to sort the array. To sort an array Alice can add 1 to any integer in the array in 1 move.

Alice wants to find a minimum number of moves needed to sort this array. Remember that after sorting the array, all elements in it should be distinct.

## HackerEarth Sorted Arrays problem solution.

`#include<bits/stdc++.h>#define LL long long int#define M 1000000007#define MM 1000000009#define reset(a) memset(a,0,sizeof(a))#define rep(i,j,k) for(i=j;i<=k;++i)#define per(i,j,k) for(i=j;i>=k;--i)#define print(a,start,end) for(i=start;i<=end;++i) cout<<a[i];#define endl "\n"#define inf 100000000000000LL pow(LL a,LL b,LL m){LL x=1,y=a;while(b > 0){if(b%2 == 1){x=(x*y);if(x>m) x%=m;}y = (y*y);if(y>m) y%=m;b /= 2;}return x%m;}LL gcd(LL a,LL b){if(b==0) return a; else return gcd(b,a%b);}LL gen(LL start,LL end){LL diff = end-start;LL temp = rand()%start;return temp+diff;}using namespace std;int a;int main()  {    ios_base::sync_with_stdio(0);    int n;    LL ans = 0;    cin >> n;    a = 0;    for(int i = 1; i <= n ; i++)      {        cin >> a[i];        if(a[i] <= a[i - 1])          {            ans = ans + a[i - 1] - a[i] + 1;            a[i]  = a[i - 1] + 1;          }      }    cout << ans;  }`