# HackerEarth ( Problem A ) Pikachu and the Game of Strings problem solution

In this HackerEarth (Problem A) Pikachu and the Game of Strings problem solution, Pikachu has recently learnt a new move s. He knows he can work hard and convert it into a stronger move t. Both the moves s and t contain the same number of letters.

In a single day, Pikachu can increase any letter of move s by one, that is, in a single day, he can convert letter A to B, C to D, M to N and so on. He can also convert letter Z to letter A.

Pikachu just realized he also has a hidden ability. It can help him increase any letter of move s by 13, that is, in a single day, he can convert letter A to letter N, B into O, M into Z, O into B and so on.

Now Pikachu wants to know the minimum number of days in which he can convert the move s into move t ?

## HackerEarth ( Problem A ) Pikachu and the Game of Strings problem solution.

`#include <bits/stdc++.h>using namespace std;int main(){    int n;    cin>>n;    string s,t;    cin>>s>>t;    int ans=0;    for(int i=0;i<n;i++){        ans+=min((t[i]-s[i]+26)%26,1+(t[i]-(s[i]+13)+52)%26);    }    cout<<ans<<endl;}`

### Second solution

`n = int(raw_input())s = raw_input()t = raw_input()def f(g):    x = ord(g[0])    y = ord(g[1])    return min((y-x)%26, (y-(x+13)%26)%26 + 1)print sum(map(f, zip(s,t)))`