HackerEarth Number of arrays problem solution

In this HackerEarth Number of arrays problem solution, You are given an array A. You need to divide this array into exactly K non-empty segments and check whether the minimum element S amongst the maximum elements amongst all segments is less than Q or not.

In other words, if we store the maximum element of each of the segments in an array P, then you have to check if a minimum element in P is less than Q or not.

HackerEarth Number of arrays problem solution.

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.FilterInputStream;
import java.io.BufferedInputStream;
import java.io.InputStream;

class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        ScanReader in = new ScanReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        Minimum_Number solver = new Minimum_Number();
        solver.solve(1, in, out);
        out.close();
    }

    static class Minimum_Number {
        public void solve(int testNumber, ScanReader in, PrintWriter out) {
            int testcases = in.scanInt();
            int N, K, Q;
            int checker, temp;
            while (testcases-- > 0) {
                N = in.scanInt();
                K = in.scanInt();
                Q = in.scanInt();
                if (K != 1) checker = Integer.MAX_VALUE;
                else checker = Integer.MIN_VALUE;
                for (int i = 0; i < N; i++) {
                    temp = in.scanInt();
                    if (K != 1) {
                        if (temp < checker) checker = temp;
                    } else if (temp > checker) checker = temp;

                }
                if (checker < Q) out.println(checker);
                else out.println("NO");

            }
        }

    }

    static class ScanReader {
        private byte[] buf = new byte[4 * 1024];
        private int index;
        private BufferedInputStream in;
        private int total;

        public ScanReader(InputStream inputStream) {
            in = new BufferedInputStream(inputStream);
        }

        private int scan() {
            if (index >= total) {
                index = 0;
                try {
                    total = in.read(buf);
                } catch (Exception e) {
                    e.printStackTrace();
                }
                if (total <= 0) return -1;
            }
            return buf[index++];
        }

        public int scanInt() {
            int integer = 0;
            int n = scan();
            while (isWhiteSpace(n)) n = scan();
            int neg = 1;
            if (n == '-') {
                neg = -1;
                n = scan();
            }
            while (!isWhiteSpace(n)) {
                if (n >= '0' && n <= '9') {
                    integer *= 10;
                    integer += n - '0';
                    n = scan();
                }
            }
            return neg * integer;
        }

        private boolean isWhiteSpace(int n) {
            if (n == ' ' || n == '\n' || n == '\r' || n == '\t' || n == -1) return true;
            else return false;
        }

    }
}

Second solution

#include<bits/stdc++.h>
using namespace std;

int Check (int Q, int K, vector<int> arr) {
   // write your code here
}

int main() {

    ios::sync_with_stdio(0);
    cin.tie(0);
    int T;
    cin >> T;
    for(int t_i=0; t_i<T; t_i++)
    {
        int N;
        cin >> N;
        int K;
        cin >> K;
        int Q;
        cin >> Q;
        vector<int> arr(N);
        for(int i_arr=0; i_arr<N; i_arr++)
        {
          cin >> arr[i_arr];
          assert(arr[i_arr]<=1e9);
        }
        sort(arr.begin(),arr.end());
        if(K==1)
        {
            if(arr[N-1]<Q)cout<<arr[N-1]<<"\n";
            else cout<<"NO\n";continue;
        }
        if(arr[0]<Q)cout<<arr[0]<<"\n";
        else cout<<"NO\n";
    }
}