Header Ad

HackerEarth Salesmen problem solution

In this HackerEarth Salesmen problem solution You are working in a salesmen company as a programmer.

There are n towns in your country and m directed roads between them. Each road has a cost person should spend on fuel. The company wants to sell goods in all n towns. There are infinitely many salesmen in the company. We can choose some positive number of salesmen and give a non-empty list of towns to each of them. Towns from the list are the towns to sell goods in. Each salesman will visit all the towns in his list in this particular order in cycle (after the last town he will return to the first town and so on). Salesman can visit other towns on his way but he will not sell goods in these towns. Two salesmen cannot sell goods in one town because it will attract unnecessary attention to your company. But for every town there must be a salesman who sell goods in this town. If salesman's list of towns consists of exactly one town then he should pay fee to stay in this town each month (each town has its own fee) or he should go for a round trip and spend money on fuel.

Your task is to calculate the minimal amount of money company must spend monthly to achieve its goals. We will assume that every salesman will spend a month to make one cycle.


HackerEarth Salesmen problem solution


HackerEarth Salesmen problem solution.

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.OutputStream;
import java.util.Arrays;
import java.util.Random;
import java.io.IOException;
import java.util.InputMismatchException;
import java.io.InputStreamReader;
import java.io.Writer;
import java.io.BufferedReader;
import java.io.InputStream;

public class Main {
public static void main(String[] args) {
InputStream inputStream = System.in;
OutputStream outputStream = System.out;
FastScanner in = new FastScanner(inputStream);
FastPrinter out = new FastPrinter(outputStream);
Salesman solver = new Salesman();
solver.solve(1, in, out);
out.close();
}

static class Salesman {
public void solve(int testNumber, FastScanner in, FastPrinter out) {
int n = in.nextInt();
int m = in.nextInt();
int[] a = in.readIntArray(n);
long[][] f = new long[n][n];
for (long[] e : f) Arrays.fill(e, Long.MAX_VALUE);
for (int i = 0; i < n; i++) {
f[i][i] = 0;
}
for (int i = 0; i < m; i++) {
int from = in.nextInt() - 1;
int to = in.nextInt() - 1;
int cost = in.nextInt();
f[from][to] = Math.min(f[from][to], cost);
}
for (int k = 0; k < n; k++) {
long[] fk = f[k];
for (int i = 0; i < n; i++) {
long[] fi = f[i];
for (int j = 0; j < n; j++) {
if (fi[k] != Long.MAX_VALUE && fk[j] != Long.MAX_VALUE) {
fi[j] = Math.min(fi[j], fi[k] + fk[j]);
}
}
}
}
final long INF = 1L << 50;
long[][] b = new long[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == j) {
b[i][j] = a[i];
} else if (f[i][j] != Long.MAX_VALUE) {
b[i][j] = f[i][j];
} else {
b[i][j] = INF;
}
}
}
ArrayUtils.shuffle(b);
int[] p = HungarianAlgorithm.getMatching(b);
long ans = 0;
for (int i = 0; i < n; i++) {
ans += b[i][p[i]];
}
out.println(ans);
}

}

static class FastScanner extends BufferedReader {
public FastScanner(InputStream is) {
super(new InputStreamReader(is));
}


public int read() {
try {
int ret = super.read();
// if (isEOF && ret < 0) {
// throw new InputMismatchException();
// }
// isEOF = ret == -1;
return ret;
} catch (IOException e) {
throw new InputMismatchException();
}
}

static boolean isWhiteSpace(int c) {
return c >= 0 && c <= 32;
}

public int nextInt() {
int c = read();
while (isWhiteSpace(c)) {
c = read();
}
int sgn = 1;
if (c == '-') {
sgn = -1;
c = read();
}
int ret = 0;
while (c >= 0 && !isWhiteSpace(c)) {
if (c < '0' || c > '9') {
throw new NumberFormatException("digit expected " + (char) c
+ " found");
}
ret = ret * 10 + c - '0';
c = read();
}
return ret * sgn;
}

public String readLine() {
try {
return super.readLine();
} catch (IOException e) {
return null;
}
}

public int[] readIntArray(int n) {
int[] ret = new int[n];
for (int i = 0; i < n; i++) {
ret[i] = nextInt();
}
return ret;
}

}

static class ArrayUtils {
static final long seed = System.nanoTime();
static final Random rand = new Random(seed);

public static <T> void shuffle(T[] a) {
for (int i = 0; i < a.length; i++) {
int j = rand.nextInt(i + 1);
T t = a[i];
a[i] = a[j];
a[j] = t;
}
}

}

static class FastPrinter extends PrintWriter {
public FastPrinter(OutputStream out) {
super(out);
}

public FastPrinter(Writer out) {
super(out);
}

}

static class HungarianAlgorithm {
static public int[] getMatching(long[][] a) {
int n = a.length;
int[] p1 = new int[n];
int[] p2 = new int[n];
long[] row = new long[n];
long[] col = new long[n];
long allMin = Long.MAX_VALUE;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
allMin = Math.min(allMin, a[i][j]);
}
}
Arrays.fill(row, allMin);
Arrays.fill(p1, -1);
Arrays.fill(p2, -1);
for (int i = 0; i < n; i++) {
if (p1[i] >= 0) {
continue;
}
boolean[] was = new boolean[n];
int[] from = new int[n];
long[] min = new long[n];
Arrays.fill(min, Long.MAX_VALUE);
int cur = i;
int curPair = -1;
do {
if (curPair >= 0) {
was[curPair] = true;
cur = p2[curPair];
}
long d = Long.MAX_VALUE;
int minPair = -1;
long[] aCur = a[cur];
for (int j = 0; j < n; j++) {
if (was[j]) {
continue;
}
long val = aCur[j] - row[cur] - col[j];
if (val < min[j]) {
min[j] = val;
from[j] = curPair;
}
if (min[j] < d) {
d = min[j];
minPair = j;
}
}
row[i] += d;
for (int j = 0; j < n; j++) {
if (was[j]) {
col[j] -= d;
row[p2[j]] += d;
} else {
min[j] -= d;
}
}
curPair = minPair;
} while (p2[curPair] >= 0);
while (from[curPair] >= 0) {
int prev = from[curPair];
p2[curPair] = p2[prev];
p1[p2[prev]] = curPair;
curPair = prev;
}
p2[curPair] = i;
p1[i] = curPair;
}
return p1;
}

}
}

Post a Comment

0 Comments