HackerEarth N-Queens problem solution

In this HackerEarth N-Queens problem solution, we have given a chessboard having N x N cells, you need to place N queens on the board in such a way that no queen attacks any other queen.

HackerEarth N-Queens problem solution.

#include<bits/stdc++.h>

using namespace std;
int mat[110][110]={0};
int n;
int state=0;
int attacked(int x, int y){
    if(mat[x][y])return 1;
    for(int i=1; i<=n; i++){
        
        if(y-i >= 1  && mat[x][y-i])return 1;
        if(y+i <= n && mat[x][y+i])return 1;
        if(x-i >= 1 && mat[x-i][y])return 1;
        if(x+i <= n && mat[x+i][y])return 1;
        if(x-i >= 1 && y-i >= 1 && mat[x-i][y-i])return 1;
        if(x+i <= n && y+i <= n && mat[x+i][y+i])return 1;
        if(x+i <= n && y-i >= 1 && mat[x+i][y-i])return 1;
        if(x-i >= 1 && y+i <= n && mat[x-i][y+i])return 1;
    }
    return 0;
}

void print(){
    cout<<endl;
    for(int i=1; i<=n; i++){
        for(int j=1; j<=n; j++)
        cout<<mat[i][j]<<" ";
        cout<<endl;
    }
    cout<<endl;
}

int solve(int x){
    if(x == 0){
        print();
        return 1;
    }
    for(int i=1; i<=n; i++){
        for(int j=1; j<=n; j++){
            if(attacked(i, j) == 1)continue;
            mat[i][j] = 1;
            if(solve(x-1))return 1;
            mat[i][j] = 0;
        }
    }
    return 0;
}

int main(){
    cin>>n;
    if(solve(n))
    for(int i=1; i<=n; i++){
        for(int j=1; j<=n; j++)
        cout<<mat[i][j]<<" ";
        cout<<endl;
    }
    else
        cout<<"Not possible\n";
    return 0;
}