# Hackerrank Print in Reverse problem solution

In this HackerRank Print in Reverse problem, we need to develop a program in which if we have given a pointer to the head of a singly linked list then we need to print each value of the linked list in the reversed order. and if the given list is empty, then we don't need to print anything.

## Problem solution in Python programming.

```#!/bin/python3

import math
import os
import random
import re
import sys

def __init__(self, node_data):
self.data = node_data
self.next = None

def __init__(self):
self.tail = None

def insert_node(self, node_data):

else:
self.tail.next = node

self.tail = node

while node:
print(node.data, end='')

node = node.next

if node:
print(sep, end='')

elements = []
elements = elements[::-1]

for element in elements:
print (element)

if __name__ == '__main__':
tests = int(input())

for tests_itr in range(tests):
llist_count = int(input())

for _ in range(llist_count):
llist_item = int(input())
llist.insert_node(llist_item)

## Problem solution in Java Programming.

```import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

public int data;

this.data = nodeData;
this.next = null;
}
}

this.tail = null;
}

public void insertNode(int nodeData) {

} else {
this.tail.next = node;
}

this.tail = node;
}
}

while (node != null) {
System.out.print(node.data);

node = node.next;

if (node != null) {
System.out.print(sep);
}
}
}

// print list of head node

// After everything else is printed

}

private static final Scanner scanner = new Scanner(System.in);

public static void main(String[] args) {
int tests = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

for (int testsItr = 0; testsItr < tests; testsItr++) {

int llistCount = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

for (int i = 0; i < llistCount; i++) {
int llistItem = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

llist.insertNode(llistItem);
}

}

scanner.close();
}
}
```

### Problem solution in C++ programming.

```#include <bits/stdc++.h>

using namespace std;

public:
int data;

this->data = node_data;
this->next = nullptr;
}
};

public:

this->tail = nullptr;
}

void insert_node(int node_data) {

} else {
this->tail->next = node;
}

this->tail = node;
}
};

while (node) {
cout << node->data;

node = node->next;

if (node) {
cout << sep;
}
}
}

while (node) {
node = node->next;

free(temp);
}
}

return;
}

}

int main()
{
int tests;
cin >> tests;
cin.ignore(numeric_limits<streamsize>::max(), '\n');

for (int tests_itr = 0; tests_itr < tests; tests_itr++) {

int llist_count;
cin >> llist_count;
cin.ignore(numeric_limits<streamsize>::max(), '\n');

for (int i = 0; i < llist_count; i++) {
int llist_item;
cin >> llist_item;
cin.ignore(numeric_limits<streamsize>::max(), '\n');

llist->insert_node(llist_item);
}

}

return 0;
}
```

### Problem solution in C programming.

```#include <assert.h>
#include <limits.h>
#include <math.h>
#include <stdbool.h>
#include <stddef.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int data;
};

};

node->data = node_data;
node->next = NULL;

return node;
}

} else {
}

}

while (node) {
printf("%d", node->data);

node = node->next;

if (node) {
printf("%s", sep);
}
}
}

while (node) {
node = node->next;

free(temp);
}
}

else{
}

}

int main()
{
char* tests_endptr;
int tests = strtol(tests_str, &tests_endptr, 10);

if (tests_endptr == tests_str || *tests_endptr != '\0') { exit(EXIT_FAILURE); }

for (int tests_itr = 0; tests_itr < tests; tests_itr++) {
llist->tail = NULL;

char* llist_count_endptr;
int llist_count = strtol(llist_count_str, &llist_count_endptr, 10);

if (llist_count_endptr == llist_count_str || *llist_count_endptr != '\0') { exit(EXIT_FAILURE); }

for (int i = 0; i < llist_count; i++) {
char* llist_item_endptr;
int llist_item = strtol(llist_item_str, &llist_item_endptr, 10);

if (llist_item_endptr == llist_item_str || *llist_item_endptr != '\0') { exit(EXIT_FAILURE); }

}

}

return 0;
}

size_t alloc_length = 1024;
size_t data_length = 0;
char* data = malloc(alloc_length);

while (true) {
char* cursor = data + data_length;
char* line = fgets(cursor, alloc_length - data_length, stdin);

if (!line) { break; }

data_length += strlen(cursor);

if (data_length < alloc_length - 1 || data[data_length - 1] == '\n') { break; }

size_t new_length = alloc_length << 1;
data = realloc(data, new_length);

if (!data) { break; }

alloc_length = new_length;
}

if (data[data_length - 1] == '\n') {
data[data_length - 1] = '\0';
}

data = realloc(data, data_length);

return data;
}```

### Problem solution in JavaScript programming.

```'use strict';

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
inputString += inputStdin;
});

process.stdin.on('end', _ => {
inputString = inputString.replace(/\s*\$/, '')
.split('\n')
.map(str => str.replace(/\s*\$/, ''));

main();
});

return inputString[currentLine++];
}

constructor(nodeData) {
this.data = nodeData;
this.next = null;
}
};

constructor() {
this.tail = null;
}

insertNode(nodeData) {

} else {
this.tail.next = node;
}

this.tail = node;
}
};

while (node != null) {
process.stdout.write(String(node.data));

node = node.next;

if (node != null) {
process.stdout.write(sep);
}
}
}