Hackerrank Insertion Sort - Part 2 problem solution

In this Hackerrank Insertion Sort - Part 2 problem we have given a sorted list and we need to print the list or array after each insertion of the insertion sort.

Problem solution in Python programming.

import sys

def insertionSort():
    arlen = int(sys.stdin.readline())
    temp_ar = sys.stdin.readline().split()
    ar = []
    for a in temp_ar:
        ar.append(int(a))
    i = 1
    switch = False
    while(i < len(ar)):
        j = i
        switch = False
        while(ar[j] < ar[j-1] and j > 0):
            ar[j], ar[j-1] = ar[j-1], ar[j]
            switch = True
            j -= 1
        i += 1
        for num in ar:
            print(num,'',end='')
            if ar.index(num) == len(ar)-1:
                print()
                
            
insertionSort()

Problem solution in Java Programming.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int s = in.nextInt();
        int[] ar = new int[s];
        for(int i = 0; i < s; i++){
            ar[i] = in.nextInt();
        }
        insertionSort(ar);
    }
        
    public static void insertionSort(int[] ar){
        int a; int b;
        for(a = 0, b = a + 1; b < ar.length; a++, b++){
            int temp = ar[b];
            int i = a;
            while(i >= 0 && temp < ar[i]){
                ar[i + 1] = ar[i];
                i--;
            }
            ar[i + 1] = temp;
            for(int j = 0; j < ar.length; j++){
                System.out.print(ar[j] + " ");
            }
            System.out.print("\n");
        }
        
    }   
    
}

Problem solution in C++ programming.

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

#define N 1010

int s;
int ar[N];
void print() {
    for (int i = 0; i < s - 1; i ++) cout << ar[i] << ' ';
    cout << ar[s - 1] << endl; 
}
int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */   
    cin >> s;
    for (int i = 0; i < s; i ++) cin >> ar[i];
    for (int i = 1; i < s; i ++) {
        int val = ar[i], pre = i - 1;
        while (pre >= 0 && ar[pre] > val) {
            ar[pre + 1] = ar[pre];
            pre --;
        }
        ar[pre + 1] = val;
        print();
    }
    return 0;
}

Problem solution in C programming.

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <assert.h>

/* Head ends here */
void insertionSort(int ar_size, int *  ar) {
    for (int i = 1; i < ar_size; ++i) {
        int j = i - 1;
        int p = ar[i];
        while (j >= 0 && p < ar[j]) {
            ar[j+1] = ar[j];
            j--;
        }
        ar[j+1] = p;
        printf("%d", ar[0]);
        for (int k = 1; k < ar_size; ++k) {
            printf(" %d", ar[k]);
        }
        printf("\n");
    }
}

/* Tail starts here */
int main() {
   
   int _ar_size;
scanf("%d", &_ar_size);
int _ar[_ar_size], _ar_i;
for(_ar_i = 0; _ar_i < _ar_size; _ar_i++) { 
   scanf("%d", &_ar[_ar_i]); 
}

insertionSort(_ar_size, _ar);
   
   return 0;
}

Problem solution in JavaScript programming.

function processData(input) {
    for(var j = 1; j < input.length; j++) {
        var unsorted = input[j];
        
        for(var i = j-1; i > -1; i--) {
            if(unsorted < input[i]) {
                input[i+1] = input[i];
                input[i] = unsorted;
            } else {
                input[i+1] = unsorted;
                break;
            }
        }

        console.log(input.join(' '));
    }
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   _input = _input.split("\n");
   _input = _input[1].split(" ").map(function(i) { return parseInt(i) });
   processData(_input);
});