# HackerRank Day 5: Poisson Distribution II | 10 Days of Statistics solution

In this Hackerrank Day 5: Poisson Distribution II 10 Days of Statistics problem a manager of an industrial plant is planning to buy a machine of either A or type B. on the first line we need to print the expected daily cost of machine A and on the second line, we need to print the expected daily cost of machine B.

## Problem solution in Python programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
# Input from stdin
averageX, averageY = [float(num) for num in input().split(" ")]

# Cost
CostX = 160 + 40*(averageX + averageX**2)
CostY = 128 + 40*(averageY + averageY**2)

print(round(CostX, 3))
print(round(CostY, 3))```

## Problem solution in Java Programming.

```import java.io.*;
import java.util.*;

public class Solution {

public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
Scanner scan=new Scanner(System.in);
double XA=scan.nextDouble();
double XB=scan.nextDouble();
System.out.format("%.3f%n%.3f",160+40*(XA+XA*XA),128+40*(XB+XB*XB));
}
}```

## Problem solution in C++ programming.

```#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
double dMeanA = 0;
double dMeanB = 0;
cin >> dMeanA >> dMeanB;

double dExpectedA = dMeanA + pow(dMeanA,2);
double dExpectedB = dMeanB + pow(dMeanB,2);

double dCostA = 160 + 40 * dExpectedA;
double dCostB = 128 + 40 * dExpectedB;

printf("%.3f\n", dCostA);
printf("%.3f\n", dCostB);
return 0;
}```

## Problem solution in C programming.

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

/* Enter your code here. Read input from STDIN. Print output to STDOUT */
double mean1 = 0.88;
double mean2 = 1.55;
printf("%.3f\n", (double) (160 + 40 * (mean1 + (mean1 * mean1))));
printf("%.3f\n", (double) (128 + 40 * (mean2 + (mean2 * mean2))));
return 0;
}```

## Problem solution in JavaScript programming.

```function processData(input) {
//Enter your code here
console.log((160 + (40*(Math.pow(0.88, 2) + 0.88))).toFixed(3));
console.log((128 + (40*(Math.pow(1.55, 2) + 1.55))).toFixed(3));
}

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});

process.stdin.on("end", function () {
processData(_input);
});```