HackerRank Day 5: Poisson Distribution II | 10 Days of Statistics solution

In this Hackerrank Day 5: Poisson Distribution II 10 Days of Statistics problem a manager of an industrial plant is planning to buy a machine of either A or type B. on the first line we need to print the expected daily cost of machine A and on the second line, we need to print the expected daily cost of machine B.

Problem solution in Python programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
# Input from stdin
averageX, averageY = [float(num) for num in input().split(" ")]

# Cost
CostX = 160 + 40*(averageX + averageX**2)
CostY = 128 + 40*(averageY + averageY**2)

print(round(CostX, 3))
print(round(CostY, 3))

Problem solution in Java Programming.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner scan=new Scanner(System.in);
        double XA=scan.nextDouble();
        double XB=scan.nextDouble();
        System.out.format("%.3f%n%.3f",160+40*(XA+XA*XA),128+40*(XB+XB*XB));
    }
}

Problem solution in C++ programming.

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */   
    double dMeanA = 0;
    double dMeanB = 0;
    cin >> dMeanA >> dMeanB;

    double dExpectedA = dMeanA + pow(dMeanA,2);
    double dExpectedB = dMeanB + pow(dMeanB,2);

    double dCostA = 160 + 40 * dExpectedA;
    double dCostB = 128 + 40 * dExpectedB;

    printf("%.3f\n", dCostA);
    printf("%.3f\n", dCostB);
    return 0;
}

Problem solution in C programming.

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    
    double mean1 = 0.88;
    double mean2 = 1.55;
    printf("%.3f\n", (double) (160 + 40 * (mean1 + (mean1 * mean1))));
    printf("%.3f\n", (double) (128 + 40 * (mean2 + (mean2 * mean2))));
    return 0;
}

Problem solution in JavaScript programming.

function processData(input) {
    //Enter your code here
    console.log((160 + (40*(Math.pow(0.88, 2) + 0.88))).toFixed(3));
    console.log((128 + (40*(Math.pow(1.55, 2) + 1.55))).toFixed(3));
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});