In this **HackerRank Linked Lists: Detect a Cycle Interview preparation kit** problem You need to Complete the function has_cycle that must return a boolean true if the graph contains a cycle, or false.

## Problem solution in Python programming.

""" Detect a cycle in a linked list. Note that the head pointer may be 'None' if the list is empty. A Node is defined as: class Node(object): def __init__(self, data = None, next_node = None): self.data = data self.next = next_node """ def has_cycle(head): if head is None or head.next is None: return False head.visited = True current = head while current.next is not None: current = current.next if current.visited: return True return False

## Problem solution in Java7 Programming.

```
/*
Detect a cycle in a linked list. Note that the head pointer may be 'null' if the list is empty.
A Node is defined as:
class Node {
int data;
Node next;
}
*/
boolean hasCycle(Node head) {
if (head == null) return false;
Node slow = head;
Node fast = head.next;
while (slow != fast) {
if (fast == null || fast.next == null) return false;
slow = slow.next;
fast = fast.next.next;
}
return true;
}
```

### Problem solution in C++ programming.

```
/*
Detect a cycle in a linked list. Note that the head pointer may be 'NULL' if the list is empty.
A Node is defined as:
struct Node {
int data;
struct Node* next;
}
*/
bool has_cycle(Node* head) {
// Complete this function
// Do not write the main method
if ( NULL == head )
return false;
Node *temp = head;
Node **visit = new Node *[200];
int num=0;
while (temp )
{
for (int i=0; i<num; i++)
{
if ( visit[i] == temp )
{
delete [] visit;
return true;
}
}
visit[num++] =temp;
temp = temp->next;
}
return false;
}
```

## 1 Comments

In the given problem where is mentioned that we can use node.visited in python code given?

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