In this Validating UID problem, ABCXYZ company has up to 100 employees. The company decides to create a unique identification number (UID) for each of its employees. The company has assigned you the task of validating all the randomly generated UIDs.

## Problem solution in Python 2 programming.

```import re
for i in range(int(raw_input())):
N = raw_input().strip()
if N.isalnum() and len(N) == 10:
if bool(re.search(r'(.*[A-Z]){2,}',N)) and bool(re.search(r'(.*[0-9]){3,}',N)):
if re.search(r'.*(.).*\1+.*',N):
print 'Invalid'
else:
print 'Valid'
else:
print 'Invalid'
else:
print 'Invalid'```

## Problem solution in Python 3 programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
import re

for _ in range(int(input())):
u = ''.join(sorted(input()))
try:
assert re.search(r'[A-Z]{2}', u)
assert re.search(r'\d\d\d', u)
assert not re.search(r'[^a-zA-Z0-9]', u)
assert not re.search(r'(.)\1', u)
assert len(u) == 10
except:
print('Invalid')
else:
print('Valid')```

### Problem solution in pypy programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT

ids = []
line_num = int(raw_input())
while line_num:
ids.append(raw_input());
line_num -= 1;

import re

for id in ids:
chars_count = {char:id.count(char) for char in id}
upper = 0
not_alnum = 0;
dig = 0;
for ch in id:
if ch.isupper(): upper += 1
if not ch.isalnum(): not_alnum = 1;
if ch.isdigit(): dig += 1;

if len(id) != 10: print 'Invalid'
elif len(set(chars_count.values())) != 1: print 'Invalid'
elif upper < 2: print 'Invalid'
elif dig < 3: print 'Invalid'
elif not_alnum: print 'Invalid'
else: print 'Valid'```

### Problem solution in pypy3 programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
import re

def valid_uid(uid):
if len(re.findall(r"[A-Z]", uid)) < 2 or \
len(re.findall(r"[0-9]", uid)) < 3 or \
not re.match(r"[A-Za-z0-9]{10}\$", uid) or \
len(set(uid)) != len(uid):
return False

return True

n = int(input())
for _ in range(n):
uid = input()
if valid_uid(uid):
print("Valid")
else:
print("Invalid")```