HackerRank Printing Pattern using loops in c solution

In this HackerRank Printing Patterns using loops in c problem solution Print a pattern of numbers from 1 to n as shown below. Each of the numbers is separated by a single space.

4 4 4 4 4 4 4

4 3 3 3 3 3 4

4 3 2 2 2 3 4

4 3 2 1 2 3 4

4 3 2 2 2 3 4

4 3 3 3 3 3 4

4 4 4 4 4 4 4

HackerRank printing pattern using loops problem solution in c programming.

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <stdio.h>

int main()
{

int n;
scanf("%d", &n);
int len = n*2 - 1;
for(int i=0;i<len;i++){
for(int j=0;j<len;j++){
int min = i < j ? i : j;
min = min < len-i ? min : len-i-1;
min = min < len-j-1 ? min : len-j-1;
printf("%d ", n-min);
}
printf("\n");
}
return 0;
}
```

Second solution

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <stdio.h>

int main() {

int n;
scanf("%d", &n);
int len = 2*n-1;
int min1,min2,min;
// Complete the code to print the pattern.
// for rows
for (int i=1; i <=len; i++) {
// for col
for (int j=1; j<=len; j++) {
// min diff btn vertical sides
min1 = i<=len-i ? i -1 : len-i;
// min diff btn horizontal sides
min2 = j<=len-j ? j -1: len-j;
// min diff btn vertical & horizontal sides
min = min1<=min2 ? min1 : min2;
// print
printf("%d ",n-min);
}
printf("\n");
}
return 0;
}```