In this HackerRank Pointers in C programming problem solution, In this challenge, you will learn to implement the basic functionalities of pointers in C. A pointer in C is a way to share a memory address among different contexts (primarily functions). They are primarily used whenever a function needs to modify the content of a variable that it does not own.
In order to access the memory address of a variable, val, prepend it with & sign. For example, &val returns the memory address of val.
This memory address is assigned to a pointer and can be shared among various functions. For example, int*p = &val will assign the memory address of val to pointer p. To access the content of the memory to which the pointer points, prepend it with a *. For example, *p will return the value reflected by val and any modification to it will be reflected at the source (val).
void increment(int *v) {
(*v)++;
}
int main() {
int a;
scanf("%d", &a);
increment(&a);
printf("%d", a);
return 0;
}
Task
Complete the function void update(int *a,int *b). It receives two integer pointers, int* a and int* b. Set the value of a to their sum, and b to their absolute difference. There is no return value, and no return statement is needed.
a' = a + b
b' = |a - b|
HackerRank Pointers in c programming problem solution.
#include <stdio.h> void update(int *a,int *b) { // Complete this function *a=*a+*b; *b=abs(*a-(2**b)); } int main() { int a, b; int *pa = &a, *pb = &b; scanf("%d %d", &a, &b); update(pa, pb); printf("%d\n%d", a, b); return 0; }
Second solution
#include <stdio.h> #include <stdlib.h> void update(int *a,int *b) { // Complete this function int t1, t2; t1 = *a + *b; t2 = abs(*a - *b); *a = t1; *b = t2; } int main() { int a, b; int *pa = &a, *pb = &b; scanf("%d %d", &a, &b); update(pa, pb); printf("%d\n%d", a, b); return 0; }
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