HackerRank Pointers in C programming solution

In this HackerRank Pointers in C programming problem solution, In this challenge, you will learn to implement the basic functionalities of pointers in C. A pointer in C is a way to share a memory address among different contexts (primarily functions). They are primarily used whenever a function needs to modify the content of a variable that it does not own.

In order to access the memory address of a variable, val, prepend it with & sign. For example, &val returns the memory address of val.

This memory address is assigned to a pointer and can be shared among various functions. For example, int*p = &val will assign the memory address of val to pointer p. To access the content of the memory to which the pointer points, prepend it with a *. For example, *p will return the value reflected by val and any modification to it will be reflected at the source (val).

void increment(int *v) {

        (*v)++; 

    }

      int main() {

        int a;

        scanf("%d", &a);

        increment(&a);

        printf("%d", a);

    return 0;      

    }     

Task

Complete the function void update(int *a,int *b). It receives two integer pointers, int* a and int* b. Set the value of a to their sum, and b to their absolute difference. There is no return value, and no return statement is needed.

a' = a + b

b' = |a - b|


HackerRank Pointers in C programming solution


HackerRank Pointers in c programming problem solution.

#include <stdio.h>

void update(int *a,int *b) {
    // Complete this function 
    *a=*a+*b;
    *b=abs(*a-(2**b));   
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);

    return 0;
}


Second solution

#include <stdio.h>
#include <stdlib.h>

void update(int *a,int *b) {
    // Complete this function
    int t1, t2;
    t1 = *a + *b;
    t2 = abs(*a - *b);
    *a = t1;
    *b = t2;
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);

    return 0;
}


Post a Comment

0 Comments