# HackerRank Overload Operators solution in c++ programming

In this HackerRank Overload Operators problem in the c++ programming language You need to overload operators + and << for the Complex class.

## HackerRank Overload Operators problem solution in c++ programming.

```//Operator Overloading

#include<iostream>

using namespace std;

class Complex
{
public:
int a,b;
void input(string s)
{
int v1=0;
int i=0;
while(s[i]!='+')
{
v1=v1*10+s[i]-'0';
i++;
}
while(s[i]==' ' || s[i]=='+'||s[i]=='i')
{
i++;
}
int v2=0;
while(i<s.length())
{
v2=v2*10+s[i]-'0';
i++;
}
a=v1;
b=v2;
}
};

//Overload operators + and << for the class complex
//+ should add two complex numbers as (a+ib) + (c+id) = (a+c) + i(b+d)
//<< should print a complex number in the format "a+ib"
ostream& operator<<(ostream& os, const Complex& c) {
return os << c.a << (c.b > 0 ? '+' : '-') << 'i' << c.b;
}

Complex operator+(const Complex& a, const Complex& b) {
return { a.a + b.a, a.b + b.b };
}

int main()
{
Complex x,y;
string s1,s2;
cin>>s1;
cin>>s2;
x.input(s1);
y.input(s2);
Complex z=x+y;
cout<<z<<endl;
}
```

## Second solution

```//Operator Overloading

#include<iostream>

using namespace std;

class Complex
{
public:
int a,b;
void input(string s)
{
int v1=0;
int i=0;
while(s[i]!='+')
{
v1=v1*10+s[i]-'0';
i++;
}
while(s[i]==' ' || s[i]=='+'||s[i]=='i')
{
i++;
}
int v2=0;
while(i<s.length())
{
v2=v2*10+s[i]-'0';
i++;
}
a=v1;
b=v2;
}
};

//<< should print a complex number in the format "a+ib"

//Overload operators + and << for the class complex
//+ should add two complex numbers as (a+ib) + (c+id) = (a+c) + i(b+d)
Complex operator +(const Complex &x, const Complex &y) {
Complex z;
z.a = x.a + y.a; z.b = x.b + y.b;
return z;
}
//<< should print a complex number in the format "a+ib"
std::ostream &operator <<(std::ostream& os, const Complex &z) {
os << z.a << "+i" << z.b;
return os;
}

int main()
{
Complex x,y;
string s1,s2;
cin>>s1;
cin>>s2;
x.input(s1);
y.input(s2);
Complex z=x+y;
cout<<z<<endl;
}
```