In this HackerRank Java Int to String problem in java programming language You are given an integer n, you have to convert it into a string. If your code successfully converts n into a string s the code will print "Good job". Otherwise it will print "wrong answer".

HackerRank Java Int to String problem solution


HackerRank Java Int to String problem solution.

import java.util.*;
import java.security.*;
public class Solution {
 public static void main(String[] args) {

  DoNotTerminate.forbidExit();

  try {
   Scanner in = new Scanner(System.in);
   int n = in .nextInt();
   in.close();
   //String s=???; Complete this line below

   //Write your code here
   String s = Integer.toString(n);

   
   if (n == Integer.parseInt(s)) {
    System.out.println("Good job");
   } else {
    System.out.println("Wrong answer.");
   }
  } catch (DoNotTerminate.ExitTrappedException e) {
   System.out.println("Unsuccessful Termination!!");
  }
 }
}

//The following class will prevent you from terminating the code using exit(0)!
class DoNotTerminate {

 public static class ExitTrappedException extends SecurityException {

  private static final long serialVersionUID = 1;
 }

 public static void forbidExit() {
  final SecurityManager securityManager = new SecurityManager() {
   @Override
   public void checkPermission(Permission permission) {
    if (permission.getName().contains("exitVM")) {
     throw new ExitTrappedException();
    }
   }
  };
  System.setSecurityManager(securityManager);
 }
}

Second solution

import java.util.*;
import java.security.*;
public class Solution {
 public static void main(String[] args) {

  DoNotTerminate.forbidExit();

  try {
   Scanner in = new Scanner(System.in);
   int n = in .nextInt();
   in.close();
   //String s=???; Complete this line below

   //Write your code here
   String s = String.valueOf(n);

   
   if (n == Integer.parseInt(s)) {
    System.out.println("Good job");
   } else {
    System.out.println("Wrong answer.");
   }
  } catch (DoNotTerminate.ExitTrappedException e) {
   System.out.println("Unsuccessful Termination!!");
  }
 }
}

//The following class will prevent you from terminating the code using exit(0)!
class DoNotTerminate {

 public static class ExitTrappedException extends SecurityException {

  private static final long serialVersionUID = 1;
 }

 public static void forbidExit() {
  final SecurityManager securityManager = new SecurityManager() {
   @Override
   public void checkPermission(Permission permission) {
    if (permission.getName().contains("exitVM")) {
     throw new ExitTrappedException();
    }
   }
  };
  System.setSecurityManager(securityManager);
 }
}