In this HackerRank If-Else problem in the java programming language you have Given an integer, n, perform the following conditional actions:

  1. If n is odd, print Weird
  2. If n is even and in the inclusive range of 2 to 5, print Not Weird
  3. If n is even and in the inclusive range of 6 to 20, print Weird
  4. If n is even and greater than 20, print Not Weird

HackerRank Java If-Else problem solution


HackerRank Java If-Else problem solution.

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {



    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        scanner.close();
        if(N%2 == 0)
    {
        if(N>=2 && N<=5)
        {
            System.out.println("Not Weird");
        }
        else if(N>=6 && N<=20)
        {
            System.out.println("Weird");
        }
        else
        {
            System.out.println("Not Weird");
        } 
    }
    else
    {
        System.out.println("Weird");
    }

    }
}


A solution in Java 8 programming

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        String result;
        int N = s.nextInt();
        if(N%2 == 0) {
            if( (N >=2 && N <=5) || N > 20) {
                result = "Not Weird";
            } else {
                result = "Weird";
            }
        } else {
            result = "Weird";
        }
        System.out.println(result);
    }
}