In this HackerRank If-Else problem in the java programming language you have Given an integer, n, perform the following conditional actions:

1. If n is odd, print Weird
2. If n is even and in the inclusive range of 2 to 5, print Not Weird
3. If n is even and in the inclusive range of 6 to 20, print Weird
4. If n is even and greater than 20, print Not Weird

## HackerRank Java If-Else problem solution.

```import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

private static final Scanner scanner = new Scanner(System.in);

public static void main(String[] args) {
int N = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

scanner.close();
if(N%2 == 0)
{
if(N>=2 && N<=5)
{
System.out.println("Not Weird");
}
else if(N>=6 && N<=20)
{
System.out.println("Weird");
}
else
{
System.out.println("Not Weird");
}
}
else
{
System.out.println("Weird");
}

}
}```

## A solution in Java 8 programming

```import java.io.*;
import java.util.*;

public class Solution {

public static void main(String[] args) {
Scanner s = new Scanner(System.in);
String result;
int N = s.nextInt();
if(N%2 == 0) {
if( (N >=2 && N <=5) || N > 20) {
result = "Not Weird";
} else {
result = "Weird";
}
} else {
result = "Weird";
}
System.out.println(result);
}
}```