# HackerRank Java Exception Handling problem solution

In this HackerRank Java Exception Handling problem in java programming, You are required to compute the power of a number by implementing a calculator. Create a class MyCalculator which consists of a single method long power(int, int). This method takes two integers, n and p, as parameters and finds n^p. If either n or p is negative, then the method must throw an exception which says "n or p should not be negative". Also, if both n and p are zero, then the method must throw an exception which says "n and p should not be zero"

## HackerRank Java Exception Handling problem solution.

```import java.util.Scanner;
class MyCalculator {

public static int power(int n, int p) throws Exception{
if(n < 0 || p < 0){
throw new Exception ("n or p should not be negative.");
}else if(n==0 && p ==0){
throw new Exception("n and p should not be zero.");
}

else {
return ((int)Math.pow(n,p));
}
}
}

public class Solution {
public static final MyCalculator my_calculator = new MyCalculator();
public static final Scanner in = new Scanner(System.in);

public static void main(String[] args) {
while (in .hasNextInt()) {
int n = in .nextInt();
int p = in .nextInt();

try {
System.out.println(my_calculator.power(n, p));
} catch (Exception e) {
System.out.println(e);
}
}
}
}```

## Second solution

```import java.util.Scanner;
class MyCalculator {

public static int power(int n, int p) throws Exception{
if(n < 0 || p < 0){
throw new Exception ("n or p should not be negative.");
}else if(n==0 && p ==0){
throw new Exception("n and p should not be zero.");
}

else {
return ((int)Math.pow(n,p));
}
}
}

public class Solution {
public static final MyCalculator my_calculator = new MyCalculator();
public static final Scanner in = new Scanner(System.in);

public static void main(String[] args) {
while (in .hasNextInt()) {
int n = in .nextInt();
int p = in .nextInt();

try {
System.out.println(my_calculator.power(n, p));
} catch (Exception e) {
System.out.println(e);
}
}
}
}```