In this HackerRank Inherited code problem in the c++ programming language, The inherited code is provided for you in the locked section of your editor. Complete the code so that, when an exception is thrown, it prints Too short: n.
HackerRank Inherited code problem solution in c++ programming.
#include <iostream>
#include <string>
#include <sstream>
#include <exception>
using namespace std;
/* Define the exception here */
class BadLengthException {
private:
int n;
public:
BadLengthException(int errornumber) {
n = errornumber;
}
int what() {
return n;
}
};
bool checkUsername(string username) {
bool isValid = true;
int n = username.length();
if(n < 5) {
throw BadLengthException(n);
}
for(int i = 0; i < n-1; i++) {
if(username[i] == 'w' && username[i+1] == 'w') {
isValid = false;
}
}
return isValid;
}
int main() {
int T; cin >> T;
while(T--) {
string username;
cin >> username;
try {
bool isValid = checkUsername(username);
if(isValid) {
cout << "Valid" << '\n';
} else {
cout << "Invalid" << '\n';
}
} catch (BadLengthException e) {
cout << "Too short: " << e.what() << '\n';
}
}
return 0;
}
Second solution
#include <iostream> #include <string> #include <sstream> #include <exception> using namespace std; /* Define the exception here */ class BadLengthException { private: int n; public: BadLengthException(int errornumber) { n = errornumber; } int what() { return n; } }; bool checkUsername(string username) { bool isValid = true; int n = username.length(); if(n < 5) { throw BadLengthException(n); } for(int i = 0; i < n-1; i++) { if(username[i] == 'w' && username[i+1] == 'w') { isValid = false; } } return isValid; } int main() { int T; cin >> T; while(T--) { string username; cin >> username; try { bool isValid = checkUsername(username); if(isValid) { cout << "Valid" << '\n'; } else { cout << "Invalid" << '\n'; } } catch (BadLengthException e) { cout << "Too short: " << e.what() << '\n'; } } return 0; }
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