In this **Dot and Cross** problem, You are given two arrays A and B. Both have dimensions of N X M. Your task is to compute their matrix product.

# Problem solution in Python 2 programming.

import numpy a=int(raw_input()) m=[] n=[] for i in range(a): m.append(map(int,raw_input().split())) for i in range(a): n.append(map(int,raw_input().split())) print numpy.dot(numpy.array(m),numpy.array(n))

## Problem solution in Python 3 programming.

import numpy n=int(input()) a = numpy.array([input().split() for _ in range(n)],int) b = numpy.array([input().split() for _ in range(n)],int) m = numpy.dot(a,b) print (m)

### Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT import numpy n=int(raw_input().strip()) a=[] b=[] for i in xrange(n): t=map(int,raw_input().split()) a.append(t) for i in xrange(n): t=map(int,raw_input().split()) b.append(t) a=numpy.matrix(a) b=numpy.matrix(b) print a*b

### Problem solution in pypy3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT import numpy as np n= int(input()) a = np.array([input().split() for _ in range(n)],dtype=np.int) b = np.array([input().split() for _ in range(n)],dtype=np.int) res = [] for r in range(n): row = [np.dot(a[r,:],b[:,i]) for i in range(n)] res.append(row) res = np.array(res) print(res)

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