In this **Check Subset** problem, You are given two sets, A and b. Your job is to find whether set A is a subset of set B. If set A is a subset of set B, print True. If set A is not a subset of set B, print False.

## Problem solution in Python 2 programming.

for i in range(int(raw_input())): #More than 4 lines will result in 0 score. Do not leave a blank line also. a = int(raw_input()); A = set(raw_input().split()) b = int(raw_input()); B = set(raw_input().split()) print "True" if A.issubset(B) else "False"

## Problem solution in Python 3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT for _ in range(int(input())): x, a, z, b = input(), set(input().split()), input(), set(input().split()) print(a.issubset(b))

### Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT for case in range(int(raw_input())): element_count1, set1 = int(raw_input()), set(raw_input().split()) element_count2, set2 = int(raw_input()), set(raw_input().split()) print(len(set1.difference(set2))==0)

### Problem solution in pypy3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT for i in range(int(input())): a = int(input()); A = set(input().split()) b = int(input()); B = set(input().split()) if(len(A.difference(B))==0): print("True") else: print("False")

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