# HackerRank Sum of Digits of a Five Digit Number solution in c programming

In this HackerRank Sum of Digits of a Five Digit Number solution in c programming The modulo operator, %, returns the remainder of a division. For example, 4 % 3 = 1 and 12 % 10 = 2. The ordinary division operator, /, returns a truncated integer value when performed on integers. For example, 5 / 3 = 1. To get the last digit of a number in base 10, use 10 as the modulo divisor.

Given a five digit integer, print the sum of its digits.

## HackerRank sum of digits of a five-digit number problem solution in c programming.

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

int n;
scanf("%d", &n);
int digit, temp, sum = 0;
temp = n;
//Complete the code to calculate the sum of the five digits on n.
while(temp > 0)
{
digit = temp % 10;
sum = sum + digit;
temp = temp / 10;
}
printf("%d\n",sum);
return 0;
}
```

## Second solution

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

int n;
scanf("%d", &n);
int digit, temp, sum = 0;
temp = n;
//Complete the code to calculate the sum of the five digits on n.
while (n>0) {
sum += (n%10);
n=n/10;
}
printf("%d\n",sum);
return 0;
}```