HackerRank Time Delta problem solution in python

In this Time Delta problem, we need to develop a python program that can take a string as input and convert them in time zone and then print the difference between them in seconds.

Problem solution in Python 2 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
from datetime import datetime, timedelta

def gettime():
    s = raw_input()
    t = datetime.strptime(s[:-6], "%a %d %b %Y %H:%M:%S")
    m = int(s[-2:])  
    h = int(s[-4:-2])
    if s[-5] == '+':
        t -= timedelta(hours=h, minutes=m)
    else:
        t += timedelta(hours=h, minutes=m)
    return t
for _ in xrange(input()):
    t1 = gettime()
    t2 = gettime()
    d = abs(t1 - t2)
    #print d
    print d.days * 86400 + d.seconds

Problem solution in Python 3 programming.

import datetime

format_string = "%a %d %b %Y %H:%M:%S %z"
T = int(input())

for test in range(T):
    t1 = str(input())
    t2 = str(input())

    parsed_t1 = datetime.datetime.strptime(t1, format_string)
    parsed_t2 = datetime.datetime.strptime(t2, format_string)

    diff = parsed_t2 - parsed_t1

    print (int(abs(diff.total_seconds())))

Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
from datetime import datetime,timedelta
def timeformatter(t):
    ret = datetime.strptime(t[:-6],"%a %d %b %Y %H:%M:%S")
    if t[-5] == '-':
        ret +=  timedelta(hours=int(t[-4:-2]),minutes=int(t[-2:]))
    else :
        ret -=  timedelta(hours=int(t[-4:-2]),minutes=int(t[-2:]))
    return ret
T = int(raw_input())

for i in range(T):
    t1,t2= [timeformatter(raw_input()) for _ in range(2)]
    print abs(int((t1-t2).total_seconds()))

Problem solution in pypy3 programming.

from datetime import datetime
date_strftime =  '%a %d %b %Y %H:%M:%S %z'
a = []
count = input()
for i in range(int(count)):
    start = input()
    end = input()
    a.append(abs(
        datetime.strptime(end, date_strftime) -
        datetime.strptime(start, date_strftime)).total_seconds())
for i in range(int(count)):
    print (int(a[i]))