# HackerRank Time Delta problem solution in python

In this HackerRank Time Delta problem solution in python, we need to develop a python program that can take a string as input and convert them in time zone and then print the difference between them in seconds.

## Problem solution in Python 2 programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
from datetime import datetime, timedelta

def gettime():
s = raw_input()
t = datetime.strptime(s[:-6], "%a %d %b %Y %H:%M:%S")
m = int(s[-2:])
h = int(s[-4:-2])
if s[-5] == '+':
t -= timedelta(hours=h, minutes=m)
else:
t += timedelta(hours=h, minutes=m)
return t
for _ in xrange(input()):
t1 = gettime()
t2 = gettime()
d = abs(t1 - t2)
#print d
print d.days * 86400 + d.seconds```

## Problem solution in Python 3 programming.

```import datetime

format_string = "%a %d %b %Y %H:%M:%S %z"
T = int(input())

for test in range(T):
t1 = str(input())
t2 = str(input())

parsed_t1 = datetime.datetime.strptime(t1, format_string)
parsed_t2 = datetime.datetime.strptime(t2, format_string)

diff = parsed_t2 - parsed_t1

print (int(abs(diff.total_seconds())))```

### Problem solution in pypy programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
from datetime import datetime,timedelta
def timeformatter(t):
ret = datetime.strptime(t[:-6],"%a %d %b %Y %H:%M:%S")
if t[-5] == '-':
ret +=  timedelta(hours=int(t[-4:-2]),minutes=int(t[-2:]))
else :
ret -=  timedelta(hours=int(t[-4:-2]),minutes=int(t[-2:]))
return ret
T = int(raw_input())

for i in range(T):
t1,t2= [timeformatter(raw_input()) for _ in range(2)]
print abs(int((t1-t2).total_seconds()))
```

### Problem solution in pypy3 programming.

```from datetime import datetime
date_strftime =  '%a %d %b %Y %H:%M:%S %z'
a = []
count = input()
for i in range(int(count)):
start = input()
end = input()
a.append(abs(
datetime.strptime(end, date_strftime) -
datetime.strptime(start, date_strftime)).total_seconds())
for i in range(int(count)):
print (int(a[i]))```