# HackerRank Text Alignment problem solution in Python

In this Text alignment problem solution in python, In Python, a string of text can be aligned left, right and center. You are given a partial code that is used for generating the HackerRank Logo of variable thickness.

Your task is to replace the blank (______) with rjust, ljust or center.

## Problem solution in Python 2 programming.

```#Replace all ______ with rjust, ljust or center.

thickness = int(raw_input()) #This must me an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print (c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1)

#Top Pillars
for i in range(thickness+1):
print (c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)

#Middle Belt
for i in range((thickness+1)/2):
print (c*thickness*5).center(thickness*6)

#Bottom Pillars
for i in range(thickness+1):
print (c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)

#Bottom Cone
for i in range(thickness):
print ((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6)    ```

## Problem solution in Python 3 programming.

```#Replace all ______ with rjust, ljust or center.

thickness = int(input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))

#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))```

### Problem solution in pypy programming.

```thickness = int(raw_input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))

#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))```

### Problem solution in pypy3 programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT

thickness = int(input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))

#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))```