In this String validators problem, we need to develop a python program that can use python's inbuilt function and can take a string as input and then print that is the string containing alphanumeric characters, alphabetical characters, digits, lowercase, and an uppercase letter.

## Problem solution in Python 2 programming.

```S = raw_input()
print True if any(k in "0123456789" or k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k in "0123456789" for k in S) else False
print True if any(k in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k in "ABCDEFGHIJKLMNOPQRSTUVWXYZ" for k in S) else False```

## Problem solution in Python 3 programming.

```if __name__ == '__main__':
s = input()
print(any(a.isalnum() for a in s) )
print(any(a.isalpha() for a in s) )
print(any(a.isdigit() for a in s) )
print(any(a.islower() for a in s) )
print(any(a.isupper() for a in s) )```

### Problem solution in pypy programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
S=raw_input()
a=0
for i in range(len(S)):
if S[i].isalnum():
a+=1
if a>0:
print 'True'
else:
print 'False'

a=0
for i in range(len(S)):
if S[i].isalpha():
a+=1
if a>0:
print 'True'
else:
print 'False'

a=0
for i in range(len(S)):
if S[i].isdigit():
a+=1
if a>0:
print 'True'
else:
print 'False'

a=0
for i in range(len(S)):
if S[i].islower():
a+=1
if a>0:
print 'True'
else:
print 'False'

a=0
for i in range(len(S)):
if S[i].isupper():
a+=1
if a>0:
print 'True'
else:
print 'False'```

### Problem solution in pypy3 programming.

```if __name__ == '__main__':
s = input()
print(any(c.isalnum() for c in s))
print(any(c.isalpha() for c in s))
print(any(c.isdigit() for c in s))
print(any(c.islower() for c in s))
print(any(c.isupper() for c in s))```