In this String validators problem, we need to develop a python program that can use python's inbuilt function and can take a string as input and then print that is the string containing alphanumeric characters, alphabetical characters, digits, lowercase, and an uppercase letter.

## Problem solution in Python 2 programming.

S = raw_input() print True if any(k in "0123456789" or k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False print True if any(k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False print True if any(k in "0123456789" for k in S) else False print True if any(k in "abcdefghijklmnopqrstuvwxyz" for k in S) else False print True if any(k in "ABCDEFGHIJKLMNOPQRSTUVWXYZ" for k in S) else False

## Problem solution in Python 3 programming.

if __name__ == '__main__': s = input() print(any(a.isalnum() for a in s) ) print(any(a.isalpha() for a in s) ) print(any(a.isdigit() for a in s) ) print(any(a.islower() for a in s) ) print(any(a.isupper() for a in s) )

### Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT S=raw_input() a=0 for i in range(len(S)): if S[i].isalnum(): a+=1 if a>0: print 'True' else: print 'False' a=0 for i in range(len(S)): if S[i].isalpha(): a+=1 if a>0: print 'True' else: print 'False' a=0 for i in range(len(S)): if S[i].isdigit(): a+=1 if a>0: print 'True' else: print 'False' a=0 for i in range(len(S)): if S[i].islower(): a+=1 if a>0: print 'True' else: print 'False' a=0 for i in range(len(S)): if S[i].isupper(): a+=1 if a>0: print 'True' else: print 'False'

### Problem solution in pypy3 programming.

if __name__ == '__main__': s = input() print(any(c.isalnum() for c in s)) print(any(c.isalpha() for c in s)) print(any(c.isdigit() for c in s)) print(any(c.islower() for c in s)) print(any(c.isupper() for c in s))

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