HackerRank String validators problem solution in python

In this String validators problem solution in python, we need to develop a python program that can use python's inbuilt function and can take a string as input and then print that the string containing alphanumeric characters, alphabetical characters, digits, lowercase, and an uppercase letter.

HackerRank String validators solution in python


Problem solution in Python 2 programming.

S = raw_input()
print True if any(k in "0123456789" or k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k in "0123456789" for k in S) else False
print True if any(k in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k in "ABCDEFGHIJKLMNOPQRSTUVWXYZ" for k in S) else False


Problem solution in Python 3 programming.

if __name__ == '__main__':
    s = input()
    print(any(a.isalnum() for a in s) )
    print(any(a.isalpha() for a in s) )
    print(any(a.isdigit() for a in s) )
    print(any(a.islower() for a in s) )
    print(any(a.isupper() for a in s) )


Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
S=raw_input()
a=0
for i in range(len(S)):
    if S[i].isalnum():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'

a=0
for i in range(len(S)):
    if S[i].isalpha():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'
    
a=0
for i in range(len(S)):
    if S[i].isdigit():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'
    
a=0
for i in range(len(S)):
    if S[i].islower():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'
    
a=0
for i in range(len(S)):
    if S[i].isupper():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'


Problem solution in pypy3 programming.

if __name__ == '__main__':
    s = input()
    print(any(c.isalnum() for c in s))
    print(any(c.isalpha() for c in s))
    print(any(c.isdigit() for c in s))
    print(any(c.islower() for c in s))
    print(any(c.isupper() for c in s))


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