Hackerrank String Formatting solution in python

In this HackerRank String Formatting problem in python Given an integer, n, print the following values for each integer i from 1 to n:

  • Decimal
  • Octal
  • Hexadecimal (capitalized)
  • Binary

Hackerrank String Formatting solution in python

Problem solution in Python 2 programming.

N = int(raw_input())

width = len(str(bin(N)))-2

for num in range(1,N+1):
    for base in 'doXb':
        print '{0:{width}{base}}'.format(num, base=base, width=width),

Problem solution in Python 3 programming.

N = int(input())
l = len(bin(N)) - 2

for i in range(1, N + 1):
    f = ""
    for c in "doXb":
        if f:
            f += " "
        f += "{:>" + str(l) + c + "}"
    print(f.format(i, i, i, i))

Problem solution in PyPy programming.

n = int(raw_input())
width = len("{0:b}".format(n))
for i in xrange(1,n+1):
    print "{0:{width}d} {0:{width}o} {0:{width}X} {0:{width}b}".format(i, width=width)

Problem solution in pypy3 programming.

def print_formatted(number):
    for num in range(1,number+1): 
        for base in ('d', 'o', 'X', 'b'):
            print("{0:{width}{base}}".format(num, base=base, width=width), end=' ')

Note: in the above code in the for loop there is only one single line of code. for visibility purpose am going to cut down that line of code into another line.

Post a Comment


  1. Can you please explain Python 3 solution?

    1. 1.First of all width must match binary number length.
      So after defining the function.

      2.In line 2 he is assigning the variable with length of binary value by deducting base value length example 'ob1', for 'ox1' list goes on.

      3.In line 4 code will check all the bases all are string formatting code, built in it will filter all required values.
      last line again using string format to print width, base again for better understanding you can dig more.
      follow thislink