In this HackerRank Python If - Else problem set, we need to develop a python program that can read an integer value n. and then we need to print the Weird message on the screen if the number is odd. and if n is even and in between 2 to 5 then print Not Weird. and if the n is even and in between 6 to 20 then print Weird. and if n is even and greater than 20 then print the Not Weird on the output screen.

# Problem solution in Python 2 programming.

```#!/bin/python

import sys

N = int(raw_input().strip())

if (N%2):
print ("Weird")
elif (N>=2 and N<=5):
print ("Not Weird")
elif (N>=6 and N<=20):
print ("Weird")
else: print ("Not Weird")```

## Problem solution in Python 3 programming.

```#!/bin/python3

import math
import os
import random
import re
import sys

if __name__ == '__main__':
n = int(input().strip())

if n%2 != 0:
print("Weird")
else:
if n>=2 and n<=5:
print("Not Weird")
elif n>=6 and n<=20:
print("Weird")
else:
print("Not Weird")```

### Problem solution in pypy programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
n = int(raw_input())

if n%2 == 1:
print('Weird')
elif n>=2 and n<=5:
print('Not Weird')
elif n>=6 and n<=20:
print('Weird')
elif n>20:
print('Not Weird')```

### Problem solution in pypy3 programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
val = int(input())
output = "Weird"
if val%2 == 1:
pass
elif 2 <= val < 5:
output = "Not Weird"
elif 6 <= val <= 20:
pass
else:
output = "Not Weird"

print(output)```