In this Piling Up! problem we need to develop a python program that can read a single integer containing the number of test cases. and then we need to print yes or no on the output screen.

## Problem solution in Python 2 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT tests = int(raw_input().strip()) while tests > 0: n = int(raw_input().strip()) arr = map(int, raw_input().strip().split(' ')) Lmin = arr[:] Rmin = arr[:] for i in range(1,n): Lmin[i] = min(Lmin[i-1], arr[i]) for i in range(n-2, -1, -1): Rmin[i] = min(Rmin[i+1], arr[i]) result = 'Yes' for i in range(1,n-1): if Lmin[i] < arr[i] and Rmin[i] < arr[i]: result = 'No' break print result tests -= 1

## Problem solution in Python 3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT for t in range(int(input())): input() lst = [int(i) for i in input().split()] min_list = lst.index(min(lst)) left = lst[:min_list] right = lst[min_list+1:] if left == sorted(left,reverse=True) and right == sorted(right): print("Yes") else: print("No")

### Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT from collections import deque n = int(raw_input()) for _ in range(n): m = int(raw_input()) cubes = deque(map(int, raw_input().strip().split())) cube = '' for _ in range(m): left, right = cubes[0], cubes[-1] if left >= right: if cube >= left or cube == '': cube = left cubes.popleft() else: if cube >= right or cube == '': cube = right cubes.pop() if len(cubes) == 0: print 'Yes' else: print 'No'

### Problem solution in pypy3 programming.

# https://www.hackerrank.com/challenges/piling-up if __name__ == '__main__': for i in range(int(input())): num = int(input()) last_num = 99999999999 arr = map(int, input().split()) items = list(arr) start = 0 end = len(items) - 1 while start <= end: if items[start] > items[end]: if items[start] <= last_num: last_num = items[start] # print(items[start], last_num - items[start]) start += 1 else: print('No') break else: if items[end] <= last_num: last_num = items[end] # print(items[end], last_num - items[end]) end -= 1 else: # print(last_num - items[end]) print('No') break if start > end: print('Yes') # else: print('NO')

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