HackerRank itertools.combinations() solution in python

In this itertools.combinations() problem solution in python This tool returns the r length subsequences of elements from the input iterable. Combinations are emitted in lexicographic sorted order. So, if the input iterable is sorted, the combination tuples will be produced in sorted order.

You are given a string S. Your task is to print all possible combinations, up to size k, of the string in lexicographic sorted order.

Problem solution in Python 2 programming.

```from itertools import combinations

S,k = raw_input().split()
k = int(k)

for r in xrange(1,k+1):
print '\n'.join(sorted(''.join(sorted(c)) for c in combinations(S,r)))
```

Problem solution in Python 3 programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
from itertools import combinations

s , n  = input().split()

for i in range(1, int(n)+1):
for j in combinations(sorted(s), i):
print(''.join(j))```

Problem solution in pypy programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT
from itertools import combinations
string_number = raw_input().split()
string = string_number[0]
number = map(int, string_number[1])

def Print(given_list):
for elem in given_list:
n = len(elem)
elem_print = ""
for i in range(0, n):
elem_print+=elem[i]
print elem_print
return

for i in range(1, number[0]+1):
Print(list(combinations(sorted(string), i)))
# print list(combinations(string, number[0]))```

Problem solution in pypy3 programming.

```# Enter your code here. Read input from STDIN. Print output to STDOUT

import itertools

ll, m = input().split()

k = int(m)

for n in range(k):
for i in itertools.combinations(sorted(ll), n+1):
print("".join(i))
```