Hackerrank Day 6 Lets Review 30 days of code solution

In this HackerRank Day 6 Let's Review 30 days of code problem we have Given a string, s , of length n that is indexed from 0 to n-1, print its even-indexed and odd-indexed characters as 2 space-separated strings on a single line.

Problem solution in Python 2 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
N = int(raw_input().strip())
for i in range(N):
    str = raw_input().strip()
    funny = True
    for j in range(len(str)/2 + 1):
        if abs(ord(str[j+1]) - ord(str[j])) != abs(ord(str[len(str)-j-2]) - ord(str[len(str)-j-1])):
            funny = False
            break
    if funny:
        print "Funny"
    else:
        print "Not Funny"

Problem solution in Python 3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT

n = int(input())
temp = []
for i in range(0,n):
    s = input()
    temp.append(s)

for i in range(0,n):
    for j in range(0,len(temp[i]),2):
        print(temp[i][j],end='')
    print(end=' ')
    for j in range(1,len(temp[i]),2):
        print(temp[i][j],end='')
    print()

Problem solution in java programming.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        sc.nextLine();
        for(int i=0;i<n;i++){
            String s = sc.nextLine();
            String r = new StringBuilder(s).reverse().toString();
            char sArr[] = s.toCharArray();
            char rArr[] = r.toCharArray();
            int j = 1;
            int k = s.length();
            int flag = 1;
            while(j < k){
                if(Math.abs(sArr[j]-sArr[j-1]) != Math.abs(rArr[j]-rArr[j-1])){
                    System.out.println("Not Funny");
                    flag = 0;
                    break;
                }
                ++j;
            }
            if(flag == 1){
            System.out.println("Funny");
            }
        }
    }
}

Problem solution in c++ programming.

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    int T;
    int test;
    int N;
    cin>>T;
    string S;
    for(int j=0;j<T;j++){
        cin>>S;
        test=1;
        N=S.size();
        for(int i=1;i<N;i++){
            if(abs(S[i]-S[i-1])!=abs(S[N-i]-S[N-i-1])){
                test=0;
                break;
            }
        }
        if(test==0){
            cout<<"Not Funny"<<endl;
        } else{
            cout<<"Funny"<<endl;
        }
        
    }
    return 0;
}

Problem solution in c programming.

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */
    int n,i; // n number of arrays,

    scanf("%d",&n);
    // malloc an array of n char array pointers.
    char **array = (char**) malloc(sizeof(char *)*n);

    // allocate memory for each of the char array pointers
    for(i=0;i<n;i++) {
        array[i] = malloc(sizeof(char)*20000);
        scanf("%s",array[i]);
    }

    for(i = 0; i < n; i++) {
        int end = strlen(array[i]) - 2;
        int funnyFlag = 1;
        
        for(int j = 1; j < strlen(array[i]) - 1; j++) {       
            
            if(abs(array[i][j] - array[i][j - 1]) != abs(array[i][end] - array[i][end+1])) {                  
                funnyFlag = 0;                
                break;
            }     
            
            end--;              
        }
        
        if(funnyFlag == 1){
            printf("Funny\n");
        }else {
            printf("Not Funny\n");
        }
        free(array[i]);
    }

    free(array);
    return 0;
}

Problem solution in Javascript programming.

function funnyOrNot(word) {
    var sval;
    var rval;
    var j = word.length - 1;
    
    for (var i = 1; i < word.length; i++) {
        sval = Math.abs(word.charCodeAt(i) - word.charCodeAt(i - 1));
        rval = Math.abs(word.charCodeAt(j) - word.charCodeAt(j - 1));
        //process.stdout.write(sval + " " + rval + "\n");
        if (sval !== rval) {
            process.stdout.write("Not ");
            break;
        }
        j--;
    }
    
    process.stdout.write("Funny\n");
}

function processData(input) {
    //Enter your code here
    var pieces = input.split('\n');
    for (var i = 0; i < parseInt(pieces[0]); i++) {
        funnyOrNot(pieces[i+1]);
    }
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});